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Three solving methods every IGCSE student needs: factorisation, the quadratic formula and completing the square.
A quadratic equation has the form ax² + bx + c = 0. You can solve it by factorisation (split into two brackets and set each to zero), the quadratic formula x = (−b ± √(b² − 4ac)) / 2a, or completing the square (rewrite as a(x + p)² + q). Factorisation is Standard tier; the formula and completing the square are Higher tier. The discriminant b² − 4ac tells you how many solutions exist.
Source: Edexcel IGCSE Mathematics (9-1) Specification 4MA1
Factorisation is the fastest method when the quadratic splits cleanly into two brackets. It works on both Standard and Higher tiers and is usually worth 3–4 marks. Follow these three steps:
This method relies on the zero product property: if two things multiply to give zero, at least one of them must be zero.
When a quadratic does not factorise neatly, the quadratic formula always works. For ax² + bx + c = 0:
x = (−b ± √(b² − 4ac)) / 2a
The expression under the square root — b² − 4ac — is called the discriminant. It tells you how many real solutions the equation has:
This is a Higher tier topic. You must substitute a, b and c carefully — pay special attention to negative values, particularly when b is negative.
Completing the square rewrites ax² + bx + c in the form a(x + p)² + q. This is useful for two things: solving quadratics and finding the turning point of a parabola (the minimum or maximum is at (−p, q)).
For x² + bx + c (when a = 1), the process is:
When a ≠ 1, factor out a from the first two terms before completing the square inside the bracket. This is a common Grade 8/9 extension.
Solve x² − 2x − 15 = 0 by factorisation.
Step 1: Find two numbers that multiply to −15 and add to −2. These are +3 and −5.
Step 2: Factorise: (x + 3)(x − 5) = 0
Step 3: Set each bracket to zero: x + 3 = 0 gives x = −3, and x − 5 = 0 gives x = 5.
Answer: x = −3 or x = 5
Solve 3x² + 6x − 2 = 0. Give your answers correct to 3 significant figures.
Step 1 — Identify a, b, c: a = 3, b = 6, c = −2
Step 2 — Calculate discriminant: b² − 4ac = 36 − 4(3)(−2) = 36 + 24 = 60
Step 3 — Apply formula: x = (−6 ± √60) / (2 × 3) = (−6 ± 7.746) / 6
Step 4 — Two solutions: x = (−6 + 7.746) / 6 = 0.291 or x = (−6 − 7.746) / 6 = −2.29
Answer: x = 0.291 or x = −2.29 (3 s.f.)
Write x² − 8x + 5 in the form (x + p)² + q. Hence solve x² − 8x + 5 = 0, leaving your answer in surd form.
Step 1 — Halve coefficient of x: Half of −8 is −4.
Step 2 — Form the bracket and subtract the square: (x − 4)² − (−4)² = (x − 4)² − 16
Step 3 — Add the constant: (x − 4)² − 16 + 5 = (x − 4)² − 11
Step 4 — Solve: (x − 4)² − 11 = 0 ⇒ (x − 4)² = 11 ⇒ x − 4 = ±√11 ⇒ x = 4 ± √11
Answer: (x − 4)² − 11; solutions x = 4 + √11 or x = 4 − √11
Negative b trap: In the formula, −b means you negate b. When b is already negative (e.g. b = −6), −b becomes +6, not −6. Write substitutions explicitly to avoid sign errors.
Exact vs decimal: If the question says "surd form" or "exact value", leave your answer with √ signs. Do not convert to a decimal or you will lose marks.
Completing the square when a > 1: You must factor out a from the x² and x terms first. Forgetting this step produces the wrong p and q values and loses all method marks.
Forgetting to rearrange to = 0: You cannot factorise x² + 3x = 10 directly. Subtract 10 from both sides first to get x² + 3x − 10 = 0.
Check the question wording for answer format: "Give your answer to 2 d.p." signals the formula. "Write in the form (x + p)² + q" means completing the square. "Factorise" means factorisation only.
Show the discriminant calculation separately: Writing b² − 4ac = ... as its own line earns a method mark and helps you avoid arithmetic errors inside the square root.
Always give both solutions: Quadratic equations have two solutions (unless the discriminant is zero). Giving only one answer loses half the marks.
Substitute back to verify: On calculator papers, plug your solutions back into the original equation to check they work. This takes seconds and can save you from sign errors.
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