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Elimination, substitution and linear-quadratic pairs — the complete IGCSE guide with worked examples for grades 5-9.
For two linear equations, use the elimination method: scale the equations so one variable has matching coefficients, then apply SSS (Same Signs Subtract) or DSA (Different Signs Add) to eliminate it. For linear-quadratic pairs, use substitution: rearrange the linear equation, substitute into the quadratic, solve, and find both pairs of values.
Source: Edexcel IGCSE Mathematics (9-1) Specification 4MA1
The elimination method is a five-step process that removes one variable entirely, leaving a single equation with one unknown. Here is the process:
The mnemonic SSS and DSA is the easiest way to remember whether to add or subtract the equations. If the matching coefficients have the same sign, subtract. If they have different signs, add.
When one equation is linear and the other is quadratic (for example, a circle equation like x² + y² = 13), the substitution method is required. Elimination does not work here because the equations have different degrees.
Solve simultaneously: 5x + 2y = 11 and 3x - y = 11
Label: (1) 5x + 2y = 11 (2) 3x - y = 11
Step 1 (Scale): Multiply (2) by 2: 6x - 2y = 22 ... call this (3)
Step 2 (Eliminate y — different signs, so add): (1) + (3): 11x = 33
Step 3 (Solve): x = 3
Step 4 (Substitute into (2)): 3(3) - y = 11, so 9 - y = 11, y = -2
Check in (1): 5(3) + 2(-2) = 15 - 4 = 11. Correct.
Answer: x = 3, y = -2
Solve: y = 2x + 1 and x² + y² = 13
Step 1 (Substitute): Replace y in the quadratic: x² + (2x + 1)² = 13
Step 2 (Expand): x² + 4x² + 4x + 1 = 13
Step 3 (Simplify): 5x² + 4x - 12 = 0
Step 4 (Factorise): (5x - 6)(x + 2) = 0
Step 5 (Solve): x = 1.2 or x = -2
Step 6 (Find y): When x = 1.2: y = 2(1.2) + 1 = 3.4. When x = -2: y = 2(-2) + 1 = -3
Answer: (1.2, 3.4) and (-2, -3)
Solve: x + y = 4 and xy = 3
Step 1 (Rearrange linear): y = 4 - x
Step 2 (Substitute into xy = 3): x(4 - x) = 3
Step 3 (Expand): 4x - x² = 3, so x² - 4x + 3 = 0
Step 4 (Factorise): (x - 3)(x - 1) = 0
Step 5 (Solve): x = 3 or x = 1
Step 6 (Find y): When x = 3: y = 1. When x = 1: y = 3
Answer: (3, 1) and (1, 3)
The matching pairs trap: When a quadratic gives two x values, students sometimes pair the first x with the second y. Always substitute each x individually into the linear equation to find its corresponding y.
The square expansion trap: (2x + 1)² = 4x² + 4x + 1, not 4x² + 1. Forgetting the middle term when squaring a binomial is one of the most frequent errors on Higher papers.
Substituting into the wrong equation: After solving, always substitute back into the linear equation (not the quadratic). The linear equation is simpler and less prone to arithmetic errors.
Show method clearly: Label your equations, show scaling, and write "add" or "subtract" explicitly. Examiners award method marks at every stage.
Give answers as coordinate pairs: For linear-quadratic questions, always present your final answers as (x, y) pairs. Listing x values and y values separately risks losing presentation marks.
Check both values in both equations: Substitute your final pair(s) into both original equations to confirm they satisfy each one. This catches sign and arithmetic errors before you move on.
Expect two solution pairs: Linear-quadratic systems almost always have two solutions. If you only find one, recheck your quadratic — you may have a factorising error.
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